JEE PHYSICS MCQ: MOTION IN PLANE

1 Easy

1 of 1

Application +4 | -1

A body projected with velocity

u

at projection angle

\theta

has horizontal range

R

. For the same velocity and projection angle, its range on the moon surface will be

\left(g_{\text {moon }}=g_{\text {earth }} / 6\right)

View answer and explanation

Correct option: D

6 R

Option D (6 R) is correct because the range is inversely proportional to the acceleration due to gravity, and the moon's gravity is 1/6th of Earth's.

More Questions from MOTION IN PLANE

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\mathrm{\vec P} = \mathrm{\vec A} + \mathrm{\vec B}\,\,\mathrm{and}\,P = A + B.

\mathrm{\vec A}\,and\,\mathrm{\vec B}

0^{\circ}

90^{\circ}

\mathrm{If}\,(\mathbf{a}+3 \mathbf{b}) \cdot(7 \mathbf{a}-5 \mathbf{b})=0

(\mathbf{a}-4 \mathbf{b}) \cdot(7 \mathbf{a}-2 \mathbf{b})=0

\mathbf{a}

\mathbf{b}

\theta

\left(90^{\circ}-\theta\right)

39.2 \mathrm{~ms}^{-1}

50 \mathrm{~m}

{g}=9.8 \mathrm{~ms}^{-2}