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JEE PHYSICS MCQ: OSCILLATIONS

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A particle starts executing simple harmonic motion (SHM) of amplitude aa and total energy EE. At any instant, its kinetic energy is 3E4\frac{{3E}}{4}, then its displacement yy is given by
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Correct option: D
y=a2y = \frac{a}{2}
Option D (y=a2y = \frac{a}{2}) is correct because it is derived from the relationship between kinetic energy, total energy, amplitude, and displacement in SHM.

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