JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

n

is even, then the sum of

n

terms of the series

1^2-2^2+3^2-4^2+5^2-6^2+\ldots \ldots

, is

View answer and explanation

Correct option: A

-\frac{n(n+1)}{2}

Option A (

-\frac{n(n+1)}{2}

) is correct because the sum of the series, when n is even, can be simplified by pairing terms and summing the resulting arithmetic progression.

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