Acetic acid on warming with hydrazoic acid in presence of $conc.{{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4}$ gives:

${\rm{C}}{{\rm{H}}_3}{\rm{N}}{{\rm{H}}_2}$

${\rm{C}}{{\rm{H}}_3}{\rm{CON}}{{\rm{H}}_2}$

${\rm{C}}{{\rm{H}}_3}{\rm{COON}}{{\rm{H}}_4}$

${\rm{C}}{{\rm{H}}_3}{\rm{C}}{{\rm{H}}_2}{\rm{N}}{{\rm{H}}_2}$

JEE CHEMISTRY MCQ: ALDEHYDES & KETONES & CARBOXYLIC ACIDS

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Understanding +4 | -1

Acetic acid on warming with hydrazoic acid in presence of

conc.{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4}

gives:

View answer and explanation

Correct option: B

\mathrm{C}{\mathrm{H}_3}\mathrm{N}{\mathrm{H}_2}

Option B (

\mathrm{C}{\mathrm{H}_3}\mathrm{N}{\mathrm{H}_2}

) is correct because acetic acid reacts with hydrazoic acid in the presence of

conc.{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4}

to give methylamine.