JEE MATHEMATICS MCQ: 2D GEOMETRY SYSTEM

1 Easy

1 of 1

Application +4 | -1

The sum of squares of the distances of a moving point from two fixed points

(a, 0)

and

(-a, 0)

is equal to a constant. Then, the equation of its locus is

View answer and explanation

Correct option: B

x^2+y^2=C-a^2

Option B (

x^2+y^2=C-a^2

) is correct because it represents the locus of a point whose sum of squared distances from two fixed points is constant.

More Questions from 2D GEOMETRY SYSTEM

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\alpha

(\alpha, 2 \alpha)

\Delta A B C

A(0,2), B(2,0)

C(4,4)

P

2 P A=3 P B

A

(0,0)

B

(4,-3)

(1, \sqrt{3}),(0,0)

(2,0)

(1,5),(-3,1) \,\&\,(-2,1)

9 x^2-16 y^2-18 x+32 y-23

=0

25 x^2+9 y^2-50 x-18 y+33=0

(0,0)(3,0)

(0,4)