JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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The uncertainty in the position of an electron (mass

=

9.1 \times 10^{-28} {~g}

) moving with a velocity of

3.0 \times 10^4 {~cm} {~s}^{-1}

accurate upto

0.011 \%

will be

View answer and explanation

Correct option: C

0.175 {~cm}

Option C (

0.175 {~cm}

) is correct because it is calculated using the Heisenberg uncertainty principle, relating uncertainty in position and momentum.

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n^{\text {th }}

\mathrm{A}

\times 10^{12}

\frac{1}{{ }^{\prime} \mathrm{B}^{\prime}}

\ell = 1,\,\,m = 0

1.25 \times {10^{ - 13}} \times {A^{1/3}}\mathrm{cm}.