NEET UG PHYSICS MCQ: THERMODYNAMICS

1 Easy

1 of 1

Application +4 | -1

One mole of an ideal gas is compressed adiabatically from

6 \, \mathrm{Ltr}

2 \, \mathrm{Ltr}

. The initial pressure of the gas is

10^5 \mathrm{~N} / \mathrm{m}^2

. Then final pressure of gas is if molar specific heat of gas at constant volume

=\frac{3}{2} R .\left[(3)^{5 / 3}=6.19\right]

View answer and explanation

Correct option: A

6.19 \times 10^5 \mathrm{~N} / \mathrm{m}^2

Option A (

6.19 \times 10^5 \mathrm{~N} / \mathrm{m}^2

) is correct because the final pressure is calculated using the adiabatic process equation,

P_1V_1^\gamma = P_2V_2^\gamma

, where

\gamma = C_p/C_v

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