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JEE PHYSICS MCQ: ATOMS

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Application +4 | -1
In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series to the longest wavelength in
The Balmer series is:
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Correct option: A
527\frac{5}{{27}}
Option A (527\frac{5}{{27}}) is correct because it is calculated by finding the ratio of the longest wavelengths using the Rydberg formula for the Lyman and Balmer series.

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