A magnetic dipole is placed in two perpendicular magnetic fields ${{\rm{\vec B}}}$ and ${{\rm{\vec H}}}$ and is in equilibrium taking angle ${\rm{\theta }}$ with ${{\rm{\vec B}}}$. Then

$B\sin {\rm{\theta }} = H\cos {\rm{\theta }}$

$B\;{\rm{cos\theta }} = H\sin {\rm{\theta }}$

NEET UG PHYSICS MCQ: MAGNETISM AND MATTER

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Application +4 | -1

A magnetic dipole is placed in two perpendicular magnetic fields

{\mathrm{\vec B}}

and

{\mathrm{\vec H}}

and is in equilibrium taking angle

\mathrm{\theta }

with

{\mathrm{\vec B}}

. Then

View answer and explanation

Correct option: C

B\sin \mathrm{\theta } = H\cos \mathrm{\theta }

Option C (

B\sin \mathrm{\theta } = H\cos \mathrm{\theta }

) is correct because the torques due to the two magnetic fields must balance for equilibrium.

Practice All Chapter MCQs →

\vec A = 2\vec i - 3\vec j + 6\vec k\,{m^2}

\vec B = - 3\vec i + \vec j + 2\vec k\,\left( {Wb/{m^2}} \right)

250\;joule

10\;kg

50\;Hz

7.5\;gm/c{m^3}

M

B