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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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∫0sin⁡2x(Sin⁡−1t)dt+∫0cos⁡2x(Cos⁡−1t)dt=\int\limits_{0}^{\sin ^2 x}\left(\operatorname{Sin}^{-1} \sqrt{t}\right) d t+\int\limits_{0}^{\cos ^2 x}\left(\operatorname{Cos}^{-1} \sqrt{t}\right) d t=
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Correct option: C
π4\frac{\pi}{4}
Option C (π4\frac{{π}}{{4}}) is correct because the derivative of the given expression is zero, implying it's a constant, and evaluating it at x = pi/4 gives pi/4.

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