${\rm{CuS}}{{\rm{O}}_4}$ and $KI$ on mixing gives :

${\rm{C}}{{\rm{u}}_2}{{\rm{I}}_2} + {{\rm{K}}_2}{\rm{S}}{{\rm{O}}_4} + {{\rm{I}}_2}$

${\rm{Cu}}{{\rm{I}}_2} + {{\rm{K}}_2}{\rm{S}}{{\rm{O}}_4}$

${\rm{C}}{{\rm{u}}_2}{{\rm{I}}_2} + {{\rm{K}}_2}{\rm{S}}{{\rm{O}}_4}$

${\rm{Cu}}{{\rm{I}}_2} + {{\rm{K}}_2}{\rm{S}}{{\rm{O}}_4} + {{\rm{I}}_2}$

JEE CHEMISTRY MCQ: REDOX REACTIONS

1 Medium

1 of 1

Understanding +4 | -1

\mathrm{CuS}{\mathrm{O}_4}

and

KI

on mixing gives :

View answer and explanation

Correct option: C

\mathrm{C}{\mathrm{u}_2}{\mathrm{I}_2} + {\mathrm{K}_2}\mathrm{S}{\mathrm{O}_4} + {\mathrm{I}_2}

Option C (

\mathrm{C}{\mathrm{u}_2}{\mathrm{I}_2} + {\mathrm{K}_2}\mathrm{S}{\mathrm{O}_4} + {\mathrm{I}_2}

) is correct because Cu2+ oxidizes I- to I2, and Cu2+ is reduced to Cu+ forming Cu2I2.

Practice All Chapter MCQs →

\mathrm{H}

2 \mathrm{KClO}_3 \longrightarrow 2 \mathrm{KCl}+3 \mathrm{O}_2

\mathrm{HNO}_3

\mathrm{HNO}_3

\mathrm{MnO}_4^{-}(\mathrm{aq})+\mathrm{Br}^{-}(\mathrm{aq})+\mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{MnO}_2(\mathrm{aq})+\mathrm{BrO}_3^{-}(\mathrm{aq})+2 \mathrm{OH}^{-}(\mathrm{aq})

\mathrm{Br}

-1

+5.