JEE CHEMISTRY MCQ: AMINES

1 Hard

1 of 1

Application +4 | -1

The product formed in the reaction

n - hexanamide + \mathrm{B}{\mathrm{r}_2} + \mathrm{KOH,}

is

View answer and explanation

Correct option: D

pentanamine

Option D (pentanamine) is correct because the reaction is a Hofmann degradation, which converts an amide to an amine with one fewer carbon atom.

More Questions from AMINES

Practice All Chapter MCQs →

\mathrm{Z}

' in the sequence

{{\text{C}}_6}{{\text{H}}_5}{\text{N}}{{\text{H}}_2}\xrightarrow{{{\text{NaN}}{{\text{O}}_2} + {\text{HCl}}}}{\text{X}}\xrightarrow{{{\text{CuCN}}}}{\text{Y}}\xrightarrow{{{{\text{H}}^ + }/{{\text{H}}_2}{\text{O}}}}{\text{Z}}

The primary, secondary and tertiary amines can be distinguished by: Assertion: The main product of reaction of alcoholic silver nitrite and ethyl bromide is nitroethane.

Reason: Silver nitrite is predominantly covalent compound. Hofmann’s bromamide reaction is to convert Gabriel phthalamide synthesis is used for preparation of :- Elements found in explosive are: