Back to HYDROCARBONS

JEE CHEMISTRY MCQ: HYDROCARBONS

1 Easy

1 of 1

Application +4 | -1

In a mixture of n-hexadecane and α-methylnaphthalene the percentage of the latter is 10.The value of cetane number is:

View answer and explanation

Correct option: B

90

Option B (90) is correct because the cetane number represents the percentage of n-hexadecane in the mixture, which is 100 - 10 = 90.

More Questions from HYDROCARBONS

Practice All Chapter MCQs →

\mathrm{Ca}{\mathrm{C}_2} + {\mathrm{H}_2}\mathrm{O} \to X\xrightarrow{{{\mathrm{O}_3}/\frac{{{\mathrm{H}_2}\mathrm{O}}}{{\mathrm{O}{\mathrm{H}^ + }}}}}\mathrm{HCOOH} + \mathrm{HCOOH},X\;\mathrm{is}

In benzene, there is a delocalisation of π-electrons. Hence, each π-electron is attached by….carbon nuclei. Which statement is false? Assertion (A) In comparison to ethyl chloride, it is not easy to carry outnucleophilic substitution on vinyl chloride.

Reason (R) Vinyl group is an electron donating. If 2-oxopropanal and methanal are obtained by the reductive ozonolysis of compound (A), then the number of

\sigma

-bonds presents in Fischer-Tropsch process is used in the manufacture of: