The thermo emf of a thermo-couple is found to depend on temperature $T$ (in degree Celsius) as $E = 4\,T - \frac{{{T^2}}}{{200}}$, where $T\,{\,^0}{\rm{C}}$ is the temperature of the hot junction. The neutral and inversion temperature of the thermocouple are (in degree celsius)

$\begin{array}{*{20}{l}} {{\rm{400, 800}}} \end{array}$

$\begin{array}{*{20}{l}} {{\rm{100, 200}}} \end{array}$

$\begin{array}{*{20}{l}} {{\rm{200, 400}}} \end{array}$

$\begin{array}{*{20}{l}} {{\rm{300, 600}}} \end{array}$

JEE PHYSICS MCQ: CURRENT ELECTRICITY

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Application +4 | -1

The thermo emf of a thermo-couple is found to depend on temperature

T

(in degree Celsius) as

E = 4\,T - \frac{{{T^2}}}{{200}}

, where

T\,{\,^0}\mathrm{C}

is the temperature of the hot junction. The neutral and inversion temperature of the thermocouple are (in degree celsius)

View answer and explanation

Correct option: D

\begin{array}{llllllllllllllllllll} {\mathrm{400, 800}} \end{array}

Option D (400, 800) is correct because the neutral temperature is found by setting

\frac{dE}{dT} = 0

, and the inversion temperature is twice the neutral temperature.