NEET UG PHYSICS MCQ: ELECTRO MAGNETIC INDUCTION

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Analyzing +4 | -1

A rectangular, a square, a circular and an elliptical loop, all in the

\left( {x - y} \right)

plane, are moving out of a uniform magnetic field with a constant velocity

\vec V = v\vec i

. The magnetic field is directed along the negative

z

-axis direction. The induced

emf

, during the passage of these loops, out of the field region, will not remain constant for

View answer and explanation

Correct option: B

The circular and the elliptical loops

Option B (The circular and the elliptical loops) is correct because the rate of change of area exposed to the magnetic field is not constant for circular and elliptical loops as they move out of the field, leading to a non-constant induced emf.

More Questions from ELECTRO MAGNETIC INDUCTION

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Assertion (A): Whenever the magnetic flux linked with a closed coil changes there will be an induced emf as well as an induced current.

Reason (R): According to Faraday, the induced emf is inversely proportional to the rate of change of magnetic flux linked with a coil. The coefficient of mutual inductance of two coils is

6\,\,mH

. If the current flowing in one is

2\,\,ampere

, then the induced e.m.f. in the second coil will be The induced emf cannot be produced by: Consider the statements:
(I)If magnetic field,

\mathrm{B = 0}

, then magnetic flux is also zero.
(II)If magnetic flux,

\phi = 0,

then magnetic field is also zero. The coefficient of self inductance of a solenoid is 0.18 mH. If a rod of soft iron of relative permeability 900 is inserted, then the coefficient of self inductance (in mH ) will become nearly: A uniformly wound solenoidal coil of self inductance

1.8 \times {10^{ - 4}}

H and resistance 6 Ω is broken up into two identical coils. These identical coils are then connected in parallel across a 12 V battery of negligible resistance. The time constant of the current in the circuit 