The area bounded by $y=-x^2+2 x+3$ and $y=0$ is

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1

The area bounded by

y=-x^2+2 x+3

and

y=0

View answer and explanation

Correct option: B

\frac{32}{3}

Option B (

\frac{32}{3}

) is correct because the area bounded by the curve

y = -x^2 + 2x + 3

and

y=0

is found by integrating the function from -1 to 3, which results in

\frac{32}{3}

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