JEE MATHEMATICS MCQ: ELLIPSE

1 Easy

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Analyzing +4 | -1

If polar of

\frac{x^2}{a^2}+\frac{y^2}{b^2}=1

is always touching the parabola

y^2=4 a x

, then locus of the pole is

View answer and explanation

Correct option: D

None of these

Option D (None of these) is correct because the correct locus equation is

a^3 y^2 = -b^4 x

, which does not match any of the given options. The locus is found by applying the tangency condition.

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