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JEE MATHEMATICS MCQ: LIMITS

1 Easy
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Analyzing +4 | -1
lim⁡x→0tan⁡x−sin⁡xx3\lim\limits_{x \to 0} \frac{{\tan x - \sin x}}{{{x^3}}} is equal to
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Correct option: A
12\frac{1}{2}
Option A (12\frac{1}{2}) is correct because by applying L'Hopital's rule multiple times, the limit simplifies to 12\frac{1}{2}.

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