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JEE PHYSICS MCQ: NUCLEI

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Application +4 | -1
The half-life of 226Ra{ }^{226} {Ra} is 1602 y1602 \mathrm{~y}. Calculate the activity of 0.1 g0.1 \mathrm{~g} of RaCl2{RaCl}_2 in which all the radium is in the form of 226Ra{ }^{226} {Ra}. Taken atomic weight of Ra{Ra} to be 226 g mol−1226 \mathrm{~g} \mathrm{~mol}^{-1} and that of Cl{Cl} to be 35.5 g mol−135.5 \mathrm{~g} \mathrm{~mol}^{-1}.
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Correct option: A
2.8×1092.8 \times 10^9 disintegrations s−1\mathrm{s}^{-1}
Option A (2.8×1092.8 \times 10^9 disintegrations s−1\mathrm{s}^{-1}) is correct because it is calculated by finding the number of Radium atoms and multiplying by the decay constant.

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