The value of $\mathop {\lim }\limits_{x \to 0} \frac{{\mathop \smallint \nolimits_0^{{x^2}} \cos {t^2}dt}}{{x\sin x}}$ is

JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Application +4 | -1

The value of

\lim\limits_{x \to 0} \frac{{\int \nolimits_0^{{x^2}} \cos {t^2}dt}}{{x\sin x}}

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Correct option: B

Option B (1) is correct because L'Hopital's rule can be applied twice to evaluate the limit, resulting in 1.

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