JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

a=0.2, b=\sqrt{5}

and

x=\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\ldots \infty

, then

a^{\log _b x}=

View answer and explanation

Correct option: C

Option C (4) is correct because simplifying the expression using logarithm properties and the sum of an infinite geometric series results in 4.

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A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

A-(B \cap C)

(B \cup C)-A

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a,x,b

b,y,c

{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

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y=x-2

\sum\limits_{{i=0}}^{2012} a_i

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\log \left(\frac{a}{3 b}\right)

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\frac{3}{4}