JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Application +4 | -1

f(x)= \begin{cases}\frac{\sqrt{1+k x}-\sqrt{1-k x}}{x}, & \text { for }-1 \leq x<0 \\ 2 x^2+3 x-2, & \text { for } 0 \leq x \leq 1\end{cases}

is continuous at

x=0

, then

k

is equal to

View answer and explanation

Correct option: C

-2

Option C (-2) is correct because for the function to be continuous at x=0, the left-hand limit (LHL) must equal the right-hand limit (RHL).

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