Back to POLYMERS
NEET UG CHEMISTRY MCQ: POLYMERS
1
Easy
1 of 1
Understanding
+4 | -1
Given the polymers,
A = Nylon 6.6; B=Buna –S;C= Polythene. Arrange these in increasing order of their intermolecular force (lower to higher).
A = Nylon 6.6; B=Buna –S;C= Polythene. Arrange these in increasing order of their intermolecular force (lower to higher).
View answer and explanation
Correct option: C
Option C () is correct because the intermolecular forces increase in the order: Buna-S (weakest), Polythene, and Nylon 6,6 (strongest).
More Questions from POLYMERS
Practice All Chapter MCQs →
Arrange the following monomers in order of decreasing ability to undergo cationic polymerisation
Thiokol is a Assertion: Vulcanisation of rubber increases its tensile strength.
Reason: Sulphur cross links are formed between poly-isoprene chains during vulcanisation. Select the correct statement. Which of the following type of forces are present in vulcanized rubber? Which of the following is not an example of addition polymer?
Thiokol is a Assertion: Vulcanisation of rubber increases its tensile strength.
Reason: Sulphur cross links are formed between poly-isoprene chains during vulcanisation. Select the correct statement. Which of the following type of forces are present in vulcanized rubber? Which of the following is not an example of addition polymer?
