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JEE PHYSICS MCQ: ELECTROMAGNETIC WAVES

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Application +4 | -1
Find the displacement current developed in the space between the plates of parallel plate capacitor of capacity 2μF2 \mu \mathrm{F} when voltage is changing at a rate of 106Vs−1.10^6 \mathrm{Vs}^{-1}.
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Correct option: A
0.083333333
Option C (2 mA) is correct because the displacement current is calculated using the formula id=CdVdti_d = C \frac{dV}{dt}.

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