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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1
If ∫01ett+1dt=a\int_0^1 \frac{e^t}{t+1} d t=a, then ∫b−1be−tt−b−1 dt\int_{b-1}^b \frac{e^{-t}}{t-b-1} \,d t is equal to
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Correct option: B
−ae−b-a e^{-b}
Option B (−ae−b-a e^{-b}) is correct because after substitution and simplification, the integral is equal to −ae−b-a e^{-b}.

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