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JEE PHYSICS MCQ: NUCLEI

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Application +4 | -1
The decay constant of 238U{ }^{238} \mathrm{U} is 4.9×10−18 s−14 .9 \times 10^{-18} \mathrm{~s}^{-1}.
(a) What is the average-life of 238U?{ }^{238} \mathrm{U}?
(b) What is the half-life of 238U?{ }^{238} \mathrm{U}?
(c) By what factor does the activity of a 238U{ }^{238} \mathrm{U} sample decrease in 9×1099 \times 10^9 years?
View answer and explanation
Correct option: A
(a) 6.49×109 y;6.49 \times 10^9 \mathrm{~y}; (b) 4.5×109 y;4.5 \times 10^9 \mathrm{~y}; (c) 4
Option A ((a) 6.49×109 y;6.49 \times 10^9 \mathrm{~y}; (b) 4.5×109 y;4.5 \times 10^9 \mathrm{~y}; (c) 4) is correct because it correctly calculates the average life, half-life, and activity decrease factor using the given decay constant.

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