NEET UG CHEMISTRY MCQ: STRUCTURE OF ATOM

1 Hard

1 of 1

Analyzing +4 | -1

The de Broglie wavelength of electron of

\mathrm{He}^{+}

ion is

3.32 \mathop {\text{A}}\limits^ \circ

. If the photon emitted upon de-excitation of this

\mathrm{He}^{+}

ion is made to hit

\mathrm{H}

-atom in its ground state so as to liberate electron from it, then what will be the de Broglie wavelength of photoelectron?

View answer and explanation

Correct option: A

2.348\,\mathop {\text{A}}\limits^ \circ

Option A (

2.348\,\mathop {\text{A}}\limits^ \circ

) is correct because it involves calculating the energy of the emitted photon and then using that to find the de Broglie wavelength of the photoelectron.

More Questions from STRUCTURE OF ATOM

Practice All Chapter MCQs →

Which of the following pairs have identical values of e/m? The correct de Broglie relationship is: Assertion: Unlike sound waves, electromagnetic waves do not require medium and can move in vacuum.

Reason: The oscillating electric and magnetic fields produced by oscillating charged particles are parallel to each other and both are perpendicular to the direction of propagation of the wave. S-I: The

{p}_{{x}}

orbital has maximum electron density along the y axis and its nodal plane is xz plane.

S-II : For a given atom, for all values of

n

, the

{p}

-orbitals have the same shape, but the overall size decreases as '

n

' increases. S-I: Elements like

Rb, Cs, Tl, In, Ga

and

Sc

were discovered when their minerals were analysed by spectroscopic methods.

S-II: The element helium was discovered in the sun by spectroscopic method. In which one of the following, the number of protons is greater than number of neutrons but number of protons is less than the number of electrons?