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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
The sum to nn terms of the series 32+54+98+1716+…\frac{3}{2}+\frac{5}{4}+\frac{9}{8}+\frac{17}{16}+\ldots is equal to
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Correct option: A
n+1−2−nn+1-2^{-n}
Option D (16n(n+1)(n+2)\frac{{1}}{{6}} n(n+1)(n+2)) is correct. By finding the general term and summing the series, we get the result.

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