JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1

The least value of the function

F(x)=\int_0^x(3 \sin u+4 \cos u) \mathrm{d} u

on the interval

(5 \pi / 4,4 \pi / 3]

View answer and explanation

Correct option: D

\frac{9-4 \sqrt{3}}{2}

Option D (

\frac{9-4 \sqrt{3}}{2}

) is correct because the minimum value of the function occurs at

x = 4\pi/3

within the given interval, and the function value there is

\frac{9-4 \sqrt{3}}{2}

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