JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1

\lim \limits_{{x \rightarrow 0}} \frac{[(a-n) n x-\tan x] \sin n x}{x^2}=0

then

a

is equal to

View answer and explanation

Correct option: D

n+\frac{1}{n}

Option D (

n+\frac{1}{n}

) is correct because by using the limit condition and applying L'Hôpital's rule, the value of 'a' is found to be

n+\frac{1}{n}

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