JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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The emission spectrum of hydrogen is found to satisfy the expression for the energy change, ∆E (in joules), such that

\Delta E = 2.18 \times {10^{ - 18}}\left[ {\frac{1}{{n_1^2}} - \frac{1}{{n_2^2}}} \right]

J, where,

{n_1} = 1,2,3,\; \ldots

and

{n_2} = 2,3,4, \ldots

The spectral lines correspond to Paschen series are

View answer and explanation

Correct option: C

{n_1} = 3

and

{n_2} = 4,5,6

The correct answer is C (

{n_1} = 3

and

{n_2} = 4,5,6

) because the Paschen series corresponds to transitions where the electron falls to the n=3 energy level.

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