${{\rm{O}}_2} > {\rm{O}}_2^ + > {\rm{O}}_2^ - $

${\rm{O}}_2^ + > {{\rm{O}}_2} > {\rm{O}}_2^ - $

${\rm{O}}_2^ - > {{\rm{O}}_2} > {\rm{O}}_2^ + $

${{\rm{O}}_2} > {\rm{O}}_2^ - > {\rm{O}}_2^ + $

JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

1 Medium

1 of 1

Understanding +4 | -1

{\mathrm{O}_2} > \mathrm{O}_2^ + > \mathrm{O}_2^ -

View answer and explanation

Correct option: D

\mathrm{O}_2^ + > {\mathrm{O}_2} > \mathrm{O}_2^ -

Option D (

\mathrm{O}_2^ + > {\mathrm{O}_2} > \mathrm{O}_2^ -

) is correct because the bond order of O₂⁺ is 2.5, O₂ is 2, and O₂⁻ is 1.5, and stability increases with bond order.