JEE CHEMISTRY MCQ: CHEMICAL KINETICS

1 Hard

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Analyzing +4 | -1

The rate equation for an autocatalytic reaction

\mathrm{A}+\mathrm{R} \xrightarrow{k} \mathrm{R}+\mathrm{R} \text { is } r_{\mathrm{A}}=-\frac{\mathrm{d} C_{\mathrm{A}}}{\mathrm{dt}}=k C_{\mathrm{A}} C_{\mathrm{R}}

The rate of disappearance of reactant

\text{A}

is maximum when

View answer and explanation

Correct option: B

C_{\mathrm{A}}=C_{\mathrm{R}}

Option B (

C_{\mathrm{A}}=C_{\mathrm{R}}

) is correct because the rate of an autocatalytic reaction is maximum when the concentrations of the reactant and product are equal.

More Questions from CHEMICAL KINETICS

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\mathrm{A}_2+\mathrm{B}_2 \rightarrow 2 \mathrm{AB}

\begin{aligned} & {{\text{A}}_2}\mathop \rightleftharpoons \limits_{{{\text{k}}_{ - 1}}}^{{{\text{k}}_1}} {\text{A}} + {\text{A (fast) }} \\ & \mathrm{A}+\mathrm{B}_2 \xrightarrow{\mathrm{k}_2} \mathrm{AB}+\mathrm{B} \text { (slow) } \\ & \mathrm{A}+\mathrm{B} \rightarrow \mathrm{AB} \text { (fast) } \end{aligned}

k

(Initial\mathrm{ }conc.\mathrm{ } = a)

C_0 \sqrt{T}

C_0

T

100 \mathrm{~kJ/mol}.

75 \%

\log _{10} \frac{K_2}{K_1}

27^{\circ} \mathrm{C}

2.303 \times 8.314=19.147