Question

The dimensional formula of $\frac{1}{{{\varepsilon _0}}}\frac{{{e^2}}}{{hc}}$ is

Accepted Answer

$\left[ {{{\rm{M}}^0}{{\rm{L}}^0}{{\rm{T}}^0}{{\rm{A}}^0}} \right]$

Answer

$\left[ {{{\rm{M}}^{ - 1}}{{\rm{L}}^3}{{\rm{T}}^2}{\rm{A}}} \right]$

Answer

$\left[ {{\rm{M}}{{\rm{L}}^3}{{\rm{T}}^{ - 4}}{{\rm{A}}^{ - 2}}} \right]$

Answer

$\left[ {{{\rm{M}}^{ - 1}}{{\rm{L}}^{ - 3}}{{\rm{T}}^4}} \right]$

NEET UG PHYSICS MCQ: UNITS & MEASUREMENTS

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