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JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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If sin⁡B=15sin⁡(2A+B)\sin B=\frac{1}{5} \sin (2 A+B), then tan⁡(A+B)tan⁡A\frac{\tan (A+B)}{\tan A} is equal to
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Correct option: C
32\frac{3}{2}
Option C (32\frac{3}{2}) is correct because by applying the sine addition formula and componendo and dividendo, the ratio tan⁡(A+B)tan⁡A\frac{\tan (A+B)}{\tan A} simplifies to 32\frac{3}{2}.

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