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JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1
For each x∈Rx \in R, let [x][x] be the greatest integer less than or equal to xx. Then,
lim⁡x→1−x([x]+∣x∣)sin⁡[x]∣x∣\lim \limits_ {x \rightarrow 1^{-}} \frac{x([x]+|x|) \sin [x]}{|x|} is equal to
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Correct option: A
−sin⁡1-\sin 1
Option A (-sin⁡1\sin 1) is correct because after substituting the values for x approaching 1 from the left and simplifying, the limit evaluates to -sin⁡1\sin 1.

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