JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Application +4 | -1

Given

R_1=(3.0 \pm 0.1) \Omega, R_2=(6.0 \pm 0.2) \Omega

, then calculated as

\frac{1}{R_P}=\frac{1}{R_1}+\frac{1}{R_2}

is given by

View answer and explanation

Correct option: B

(2.0 \pm 0.1) \Omega

Option A (

5 \%

) is correct because the percentage increase in time of flight is half the percentage increase in maximum height.

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