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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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If (−1,  2)\left( { - 1,\,\,2} \right) and (2,4)\left( {2,4} \right) are two points on the curve y=f(x)y = f\left( x \right) and if g(x)g\left( x \right) is the gradient of the curve at point (x,y)\left( {x,y} \right), then the value of the integral ∫−12  g  (x)  dx\int \limits_{ - 1}^2 \,\,g\,\,\left( x \right)\,\,dx, is
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Correct option: A
2\mathrm{2}
Option A (2) is correct because the integral of the gradient g(x)g(x) is the difference in the function's values at the limits of integration, f(2)−f(−1)=4−2=2f(2) - f(-1) = 4 - 2 = 2.

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