JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Application +4 | -1

\tan \alpha, \tan \beta, \tan \gamma

are the roots of the equation

x^3-p x^2-r=0

, then the value of

\left(1+\tan ^2 \alpha\right)\left(1+\tan ^2 \beta\right)\left(1+\tan ^2 \gamma\right)

is equal to

View answer and explanation

Correct option: B

1+(p-r)^2

Option B (

1+(p-r)^2

) is correct because by using Vieta's formulas to relate the roots to the coefficients of the polynomial, and then expanding the expression

(1+\tan^2 \alpha)(1+\tan^2 \beta)(1+\tan^2 \gamma)

, we arrive at the result

1+(p-r)^2

More Questions from QUADRATIC EQUATIONS

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