$\mathop \smallint \nolimits_{ - 1}^1 \,\,\frac{{\cos \,\,{\rm{h}}\;\,\,x}}{{1\,\, + \,\,{e^{2x}}}}\,\,\;dx$ is equal to

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

\int \nolimits_{ - 1}^1 \,\,\frac{{\cos \,\,\mathrm{h}\;\,\,x}}{{1\,\, + \,\,{e^{2x}}}}\,\,\;dx

is equal to

View answer and explanation

Correct option: C

\frac{{{e^2} - 1}}{{2e}}

Option C (

\frac{{{e^2} - 1}}{{2e}}

) is correct because the integral of the given function is solved using properties of hyperbolic cosine and simplification.

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