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NEET UG CHEMISTRY MCQ: STRUCTURE OF ATOM

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Which transition in the hydrogen spectrum would have the same wavelength as the Balmer type transition, n=4 to n=2 of

\mathrm{H}{\mathrm{e}^ + }

spectrum?

View answer and explanation

Correct option: D

n=2 to n=1

Option D (n=2 to n=1) is correct because the wavelength depends on

Z^2(\frac{1}{n_1^2} - \frac{1}{n_2^2})

, and for the wavelengths to be the same, the values must be equal.

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{p}_{{x}}

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