JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Analyzing +4 | -1

f\left( x \right) = \cos x\left( {\sin x + \sqrt {{{\sin }^2}x + {{\sin }^2}\theta } } \right),

where

\theta

is a given constant, then maximum value of

f(x)

View answer and explanation

Correct option: B

\sqrt{1+\sin ^2 \theta}

Option B (

\sqrt{1+\sin ^2 \theta}

) is correct because by completing the square and using trigonometric identities, we can find the maximum value of

f(x)

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