JEE MATHEMATICS MCQ: LIMITS

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Application +4 | -1

\lim \limits_{{x \rightarrow 0}}(1+a \sin x)^{\operatorname{cosec} x}=3

, then

a

View answer and explanation

Correct option: B

\ln 3

Option B (

\ln 3

) is correct because evaluating the limit using the exponential form gives

e^a = 3

, thus

a = \ln 3

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\lim \limits_{{x \rightarrow 0}}\left(\frac{1}{x^2}-\operatorname{cosec}^2 x\right)

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