${{\rm{F}}_2}$ is formed by reacting ${{\rm{K}}_2}{\rm{Mn}}{{\rm{F}}_6}$ with

NEET UG CHEMISTRY MCQ: d & f- BLOCK ELEMENTS

1 Hard

1 of 1

Understanding +4 | -1

{\mathrm{F}_2}

is formed by reacting

{\mathrm{K}_2}\mathrm{Mn}{\mathrm{F}_6}

with

View answer and explanation

Correct option: B

\mathrm{Sb}{\mathrm{F}_5}

Option B is correct because SbF5 acts as a fluoride ion acceptor, oxidizing Mn(IV) in K2MnF6 to Mn(V) and releasing F2.

Practice All Chapter MCQs →

^\circ

{\mathrm{M}^{x + }}

\sqrt {24}