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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy
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Application +4 | -1
∫0π/2dx1+(1/6)sin⁡2x=\int\limits_{0}^{\pi / 2} \frac{d x}{1+(1 / 6) \sin ^2 x}=
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Correct option: A
π267\frac{\pi}{2} \sqrt{\frac{6}{7}}
Option A (π267\frac{\pi}{2} \sqrt{\frac{6}{7}}) is correct because after applying trigonometric identities and integrating, the result is π267\frac{\pi}{2} \sqrt{\frac{6}{7}}.

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