JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Application +4 | -1

Write the dimensions of

a b

in the relation

\mathrm{P}=\frac{\mathrm{a}-\mathrm{t}^2}{\mathrm{bx}}

, where

\mathrm{P}

is the pressure,

\mathrm{x}

is the distance and

t

is the time.

View answer and explanation

Correct option: B

\mathrm{ML}^0 \mathrm{~T}^2

Option B (

\mathrm{ML}^0 \mathrm{~T}^2

) is correct because it represents the dimensions of a/b, derived from the given relation by equating dimensions.

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