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JEE PHYSICS MCQ: ALTERNATING CURRENT

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Analyzing +4 | -1
Assertion (A): An inductance and a resistance are connected in series with an AC circuit. In this circuit, the current and the potential difference across the resistance logs behind potential difference across the inductance by an angle π2.\frac{\pi}{2}.
Reason (R): In L - R circuit, voltage leads the current by phase angle which depends on the value of inductance and resistance both.
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Correct option: B
Both assertion and reason are true but reason is not the correct explanation of assertion
Option B (Both assertion and reason are true but reason is not the correct explanation of assertion) is correct because while both statements are true, the reason doesn't directly explain the phase difference between voltage across the resistor and inductor.

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In a series RC circuit with an AC source, R=300 ΩR=300 \, \Omega, C=25 μF,ε0=50 VC=25 \, \mu \mathrm{F}, \varepsilon_0=50 \mathrm{~V} and v=50/π Hzv=50 / \pi \, \mathrm{Hz}. Find the peak current and the average power dissipated in the circuit. In a series circuit R=300Ω,L=0.9 H,C=2.0R=300 \Omega, L=0.9 \mathrm{~H}, C=2.0 μF\mu F and ω=1000 rad/sec\omega=1000 \mathrm{~rad} / \mathrm{sec}. The impedance of the circuit is: An L-C-R series circuit with a resistance of 100Ω100 \Omega is connected to 200 V200 \mathrm{~V} (AC source) and angular frequency 300 rad/s300 \, \mathrm{rad} / \mathrm{s}. When only the capacitor is removed, then the current lags behind the voltage by 60∘60^{\circ}. When only the inductor is removed the current leads the voltage by 60∘60^{\circ}. The average power dissipated in original L-C-R circuit is Assertion (A) : In series L−C⋅R,ACL-C \cdot R, \mathrm{AC} circuit, current and voltage are in same phase at resonance.

Reason (R) : In series L−C−R,ACL-C-R, \mathrm{AC} circuit, resonant frequency does not depend on the value of resistance. Hence, current at resonance does not depend on resistance.
A series L−C−RL-C-R circuit is connected to an AC\mathrm{AC} voltage source. When LL is removed from the circuit, the phase difference between current and voltage is π4\frac{\pi}{4}. If instead CC is removed from the circuit, the phase difference is again π4\frac{\pi}{4} between current and voltage. The power factor of the circuit is A capacitor in an ideal LC circuit is fully charged by a DC source. Then it is disconnected from DC source, the current in the circuit
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