JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Analyzing +4 | -1

\lim \limits_{{n \rightarrow \infty}}\left(1+\frac{1}{n^2+\cos n}\right)^{n^2+n}

is equal to

View answer and explanation

Correct option: B

e

Option B (

e

) is correct because the limit can be rewritten in the form of the definition of

e

as n approaches infinity.

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\lim \limits_{{x \rightarrow 0}}\left(\frac{1}{x^2}-\operatorname{cosec}^2 x\right)

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\lim \limits_{{x \rightarrow \infty}} x\left(e^{1 / x}-1\right)

f(x)=\frac{(x+1)^7 \sqrt{1+x^2}}{\left(x^2-x+1\right)^6}

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