JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Dimensions of specific heat are

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Correct option: D

\left[\mathrm{L}^2 \mathrm{~T}^{-2} \mathrm{~K}^{-1}\right]

The correct answer is D (

\mathrm{L}^2 \mathrm{~T}^{-2} \mathrm{~K}^{-1}

) because specific heat is energy per unit mass per unit temperature change.

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