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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
The digits of a three digit number NN are in A.P. If sum of the digits is 15 and the number obtaind by reversing the digits of the number is 594 less than the original number, then 1000N−252\frac{1000}{N-252} is equal to
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Correct option: B
5/35 / 3
Option B (5/35 / 3) is correct because by finding the digits of the number and using the given conditions, we can determine the value of the expression.

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